Relation to the Sine Function Click on the image for a detailed proof \Gamma(s)\Gamma(1-s)=\frac{\pi}{\sin(\pi s)} \Downarrow \Gamma(s)\Gamma(-s)=-\frac{\pi}{s\sin(\pi s)} \Gamma(1+s)\Gamma(1-s)=\frac{\pi s}{\sin(\pi s)} Copy to Clipboard \Gamma(s)\Gamma(1-s)=\frac{\pi}{\sin(\pi s)} \Downarrow \Gamma(s)\Gamma(-s)=-\frac{\pi}{s\sin(\pi s)} \Gamma(1+s)\Gamma(1-s)=\frac{\pi s}{\sin(\pi s)} These Relations between the Gamma Function and the Sine Function are some of the most commonly used.The demonstration we propose relies heavily on Euler’s Infinite Product. Any questions? Feel free to contact our authors at: [email protected], you will be put directly in touch with the person who wrote the text. Didn’t find what you were looking for? Keep looking through all our formulas regarding the Gamma Function! Gauss's ExpressionHankel's Loop IntegralRelation to the Logarithmic FunctionFirst Formula using the Digamma FunctionRelation to the Gamma Function 1 See all Formulas for the Gamma Function… X-twitter Pinterest